iHomeEducator, Inc.

Facebook

Thursday, February 3, 2011

Abby 7th Grade: iLiveMath Test Results

iLiveMath Results: Level 2

Number of Questions: 12

Correctly Answered: 10
Incorrectly Answered: 1
Unanswered: 1

Correct: 83%
Incorrect: 8%
Unanswered: 8%


Question 1:
A diver counted 11 Sixbar wrasse fish which were joined by 9 more. What was the total?

11 + 9 = 20
Correct Answer: 20

Question 2:
The dive counted a total of 50 moray eels and later 8 swam away. How many remain?

50 - 8 = 42
Correct Answer: 42

Question 3:
A marine biologist counted 14 Humphead wrasse fish which were joined by 2 more. What was the sum?

14 + 2 = 16
Incorrect Answer: 17
Correct Answer: 16

Question 4:
The underwater tour counted a total of 51 Stingray and later 25 swam away. How many remain?

51 - 25 = 26
Correct Answer: 26

Question 5:
In a group of 16 sea animals one fourth were sea lions. Calculate the total sea lions?

16 / 4 = 4
Correct Answer: 4

Question 6:
A site seeing family counted 9 humpback flukes and 36 lobtails. How many acrobatic whale behaviors are counted?

9 + 36 = 45
Correct Answer: 45

Question 7:
The underwater tour counted a total of 51 Chrysaora jelly and later 27 swam away. How many remain?

51 - 27 = 24
Correct Answer: 24

Question 8:
The ocean expedition counted a total of 95 Yellow boxfish and later 48 swam away. How many remain?

95 - 48 = 47
Correct Answer: 47

Question 9:
An oceanographer counted 43 Parrot fish which were joined by 37 more. What was the sum?

43 + 37 = 80
Correct Answer: 80

Question 10:
A diver counted 36 Rainbow crabs which were joined by 21 more. What was the sum?

36 + 21 = 57
Correct Answer: 57

Question 11:
In a group of 72 sea animals one half were Humphead wrasse fish. Calculate the total Humphead wrasse fish?

72 / 2 = 36
Correct Answer: 36

Question 12:
In a group of 82 sea animals one half were Orangutan Crabs. Calculate the total Orangutan Crabs?

82 / 2 = 41


(c) 2010 iHomeEducator
www.iHomeEducator.com
www.iLiveMath.blogspot.com


Sent from my iPod

No comments:

Post a Comment

Note: Only a member of this blog may post a comment.